Display MoreIt has to do with the most efficient fusion pathway, what's referred to as the D-T (Deuterium-Tritium) fuel cycle.
Deuterium-2 + Tritium-3 ---> Helium-4 +n
Where the 2 neutrons in the deuterium and the 3 in the tritium together constitute the 4 in the resultant helium atom plus a free neutron. It is this free neutron that then reacts with lithium in the D-T design to produce power in the
n + Lithium-6 ---> Tritium-3 + Helium-4
pathway.
When encountering Lithium-7, the
n + Lithium-7 ---> Tritium-3 + Helium-4 + n
pathway occurs, which fails to produce energy, but repopulates the reaction with neutrons, thus helping it continue, so a D-T reactor would contain both isotopes of Lithium.
so tl; dr: The number of neutrons is important. You can also less efficiently use Deuterium-2 + Deuterium-2 in the D-D fuel cycle.
I think there was some fusion pathway that uses vanilla hydrogen to combine with a heavier element to reduce neuton production (because energetic neutrons will cook your face) but I forget.
Ah, I see now... makes sense considering.. ty for the explanation.
Hopefully I can install this with little to no conflicts now that I'm on my machine again, lol...