Check my numbers... 50MEU from one uranium ore?

  • Seems high...
    Here's how I got to that number:
    1 ore can be used to make 8 depleted isotope cells
    In a good breeder, you use one cell (2 cells over 1/2 cycle) to recharge 8, so you net 7 (87.5%)
    That gives you 28MEU in a 4.00 eff reactor (plus the bonus EU from the breeder)
    From what I can tell, you get 50% near-depleted cells back, and 87.5% again from breeding (43.75% for each use/recharge cycle)
    After about 3 cycles of use/recharge, you only have a 50% chance of still having one of the 8 original cells left, but that gives this:


    First charge/use cycle
    7 cells
    28,000,000 EU (4 eff reactor)


    2nd cycle
    3.0625 cells
    12,250,000 EU


    3rd cycle
    1.33984375 cells
    5,359,375 EU


    4th cycle
    0.586181641 cells
    2,344,726.56 EU


    Total from 4 generations: 47,954,101.6 EU


    48MEU, plus the bonus from the breeder, per ore... that would mean my 100MEU CASUC reactor really is only burning about 2 ore per run. 8|


    and people are saying that nuclear needs a buff? :P

  • In the absolute perfect setup (perfect breeder coupled with an efficiency 5 reactor) you will get 36 million EU per Uranium Ore. At 25% returns, you get an additional multiplier of 4/3 (read up on geometric series summations to find where I get this number) on that which gives you a total of 48 million EU per ore.


    Using an efficiency 4.0 reactor means you will get (1 + 4.0*7) * 4/3 = 38.7 million EU per ore.