By teh way, any fusion of elements with more protons than iron would cost energy as IRL, although i may recommend doing so with elements with more protons than calcium.
So, anything heavier than calcium (20) would cost energy to produce.
Thats why i may suggest a new formula :
Energy required to sustain reaction = 512 * (X-20) with X being n* of protons of "product". [Anything "heavier" than calcium will cost energy, while "lighter" ones produce.]
Energy required to start reaction = 100000 + 1000X
Duration of fusion is up to you to decide how much each fusion would generate/consume.
Plasma should be only cooled on plasma generator, not consumed.
Helium plasma -> plasma generator -> gaseous helium.
For every 4 bucket of plasma, it cools down to one bucket of gas/liquid/solid
More suggestions to fusion list :
Oxygen (O, 8 ) + Oxygen (O, 8 ) = Sulfur (S, 16)
Oxygen (O, 8 ) + Nitrogen (N, 7) = Phosphor (P, 15) [Only available if forestry is installed]
Lithium (Li, 3) + Lithium (Li, 3) = Carbon (C, 6) [Coal dust]
Helium (He, 2) + Helium (He, 2) = Berylium (Be, 4) / Hydrogen (H, 1) + Lithium (Li, 3) = Berylium (Be, 4)
Lead (Pb, 82) + Oxygen (O, 8 )= Thorium (Th, 90)